Now, Let's check your answers!
Indices Exercises
Question 1
a) 243b) 343
c) 512
Question 2
a) 1⁄512b) 1⁄243
c) 1⁄256
Question 3
a) 5b) 3
c) 4
Logarithms Exercises
Question 1
4 × 4 × 4 × 4 = 256So log4(256) = 4
Question 2
0.0016 = 16/10,000 = 1/625 = 1/54 = 5-4
So log5(0.0016) = -4
So log5(0.0016) = -4
Question 3
729 = 3 × 3 × 3 × 3 × 3 × 3 = 36
So log3(729) = 6
So log3(729) = 6
Inequalities Exercises
Question 1
5x > 10Therefore
x > 10/5
= x > 2
Question 2
3x + 2 > 8
= 3x + 2 - 2 > 8 -2
= 3x > 6
= 3x/3 > 6/3
= x > 2
= 3x + 2 - 2 > 8 -2
= 3x > 6
= 3x/3 > 6/3
= x > 2
Question 3
3x - 7 < 5= 3x - 7 + 7 < 5 + 7
= 3x < 12
= 3x/3 < 12/3
= x < 4
Permutation and Combination Exercises
Question 1
= 10!/(10 - 3)!= 10 × 9 × 8
= 720
Question 2
The number of permutations of 4 letters chosen from 26 is
26P4 = 26 × 25 × 24 × 23 = 358,800
26P4 = 26 × 25 × 24 × 23 = 358,800
Question 3
= 10C5= 10!/(5!)(5!)
= (10 × 9 × 8 × 7 × 6)/(5 × 4 × 3 × 2 × 1)
= 30,240/120
= 252
Arithmetic and Geometric Progression Exercises
Question 1
xn = a + d(n - 1)The first term a = 4 (1)
The tenth term = 67
x10 = a + d(10 - 1) = 67
a + 9d = 67 (2)
4 + 9d = 67
9d = 63
d = 63 ÷ 9 = 7
The common difference is 7
Question 2
This sequence has a difference of 5 between each pair of numbers.
The values of a and d are:
a = -12
d = 5
xn = a + d(n − 1)
= -12 + 5(n − 1)
= -12 + 5n − 5
= 5n − 17
So, the 32nd term is:
x32 = 5 × 32 − 17 = 160 − 17 = 143
The values of a and d are:
a = -12
d = 5
xn = a + d(n − 1)
= -12 + 5(n − 1)
= -12 + 5n − 5
= 5n − 17
So, the 32nd term is:
x32 = 5 × 32 − 17 = 160 − 17 = 143
Question 3
This sequence has a difference of 4 between each pair of numbers.
The values of a and d are:
a = 3
d = 4
xn = a + d(n-1)
= 3 + 4(n-1)
= 3 + 4n - 4
= 4n - 1
So, the 50th term is:
x50 = 4 × 50 - 1 = 200 - 1 = 199
The values of a and d are:
a = 3
d = 4
xn = a + d(n-1)
= 3 + 4(n-1)
= 3 + 4n - 4
= 4n - 1
So, the 50th term is:
x50 = 4 × 50 - 1 = 200 - 1 = 199
Data Exercises
Question 1
D is the correct answer.The number of teeth has to be a whole number, so is discrete.
Question 2
B is the answer.B is discrete because the numbers of brothers and sisters can only be values like 0, 1, 2 etc...
The other three are all continuous because they can take any value within a range, such as 160.3 cm or 75.35 kg.
Question 3
C is the answer.The weight of a cat is continuous because it can take any value within certain limits.
Mean, Median, Mode Exercises
Question 1
Add the numbers: 8 + 9 + 13 + 18 = 48
Divide by how many numbers (i.e. we added 4 numbers).
Then 48 ÷ 4 = 12.
Divide by how many numbers (i.e. we added 4 numbers).
Then 48 ÷ 4 = 12.
Question 2
Put the numbers in order first: 3, 4, 5, 5, 5, 6, 7, 7, 8, 9
5 occurs most often, so the mode is 5
5 occurs most often, so the mode is 5
Question 3
Put the numbers in order first: 2, 2, 4, 6, 11
The median is the middle number = 4
The median is the middle number = 4
Probability Exercises
Question 1
The factors of six are 1, 2, 3 and 6, so the Number of ways it can happen = 4There are six possible scores when a die is thrown, so the Total number of outcomes = 6
So the probability that the score is a factor of six = 4/6 = 2/3
Question 2
Here are 4 Queens and 4 Kings, so the Number of ways it can happen = 8There are 52 cards altogether, so the Total number of outcomes = 52
So the probability either a king or a queen = 8/52 = 2/13
Question 3
Represent 'Heads up' by H and 'Tails up' by T.There are 8 possible ways the coin can land:
(H, H, H), (H, H, T), (H, T, H), (H, T, T),
(T, H, H), (T, H, T), (T, T, H) and (T, T, T)
Of these, 3 have one Head and two Tails: (H, T, T), (T, H, T) and (T, T, H)
So:
The Number of ways it can happen = 3
The Total number of outcomes = 8
Therefore, the probability of obtaining one head and two tails = 3/8
Standard Deviation and Variance Exercises
Question 1
Firstly find the mean:
Mean = (75 + 83 + 96 + 100 + 121 + 125) ÷ 6 = 600 ÷ 6 = 100
Next find the variance. To calculate the Variance, take each difference, square it, and then average the result:
(75 - 100)2 + (83 - 100)2 + (96 - 100)2 + (100 - 100)2 + (121 - 100)2 + (125 - 100)2
= (-25)2 + (-17)2 + (-4)2 + (0)2 + (21)2 + (25)2
= 625 + 289 + 16 + 0 + 441 + 625
= 1,996
So the Variance = 1,996 ÷ 6 = 332.66...
The Standard Deviation is just the square root of the Variance
= √(332.66...)
= 18.2 correct to 1 decimal places
Mean = (75 + 83 + 96 + 100 + 121 + 125) ÷ 6 = 600 ÷ 6 = 100
Next find the variance. To calculate the Variance, take each difference, square it, and then average the result:
(75 - 100)2 + (83 - 100)2 + (96 - 100)2 + (100 - 100)2 + (121 - 100)2 + (125 - 100)2
= (-25)2 + (-17)2 + (-4)2 + (0)2 + (21)2 + (25)2
= 625 + 289 + 16 + 0 + 441 + 625
= 1,996
So the Variance = 1,996 ÷ 6 = 332.66...
The Standard Deviation is just the square root of the Variance
= √(332.66...)
= 18.2 correct to 1 decimal places
Question 2
Firstly find the mean number of words per page:
Mean = (271 + 354 + 296 + 301 + 333 + 326 + 285 + 298 + 327 + 316 + 287 + 314) ÷ 12
= 3,708 ÷ 12
= 309
Next find the variance. To calculate the Variance, take each difference, square it, and then average the result:
(271 - 309)2 + (354 - 309)2 + (296 - 309)2 + (301 - 309)2 + (333 - 309)2 + (326 - 309)2 + (285 - 309)2 + (298 - 309)2 + (327 - 309)2 + (316 - 309)2 + (287 - 309)2 + (314 - 309)2
= (-38)2 + (45)2 + (-13)2 + (-8)2 + (24)2 + (17)2 + (-24)2 + (-11)2 + (18)2 + (7)2 + (-22)2 + (5)2
= 1,444 + 2,025 + 169 + 64 + 576 + 289 + 576 + 121 + 324 + 49 + 484 + 25
= 6,146
So the Variance = 6,146 ÷ 12 = 512.166...
The Standard Deviation is just the square root of the Variance
= √(512.166...)
= 22.6 correct to 1 decimal place
Mean = (271 + 354 + 296 + 301 + 333 + 326 + 285 + 298 + 327 + 316 + 287 + 314) ÷ 12
= 3,708 ÷ 12
= 309
Next find the variance. To calculate the Variance, take each difference, square it, and then average the result:
(271 - 309)2 + (354 - 309)2 + (296 - 309)2 + (301 - 309)2 + (333 - 309)2 + (326 - 309)2 + (285 - 309)2 + (298 - 309)2 + (327 - 309)2 + (316 - 309)2 + (287 - 309)2 + (314 - 309)2
= (-38)2 + (45)2 + (-13)2 + (-8)2 + (24)2 + (17)2 + (-24)2 + (-11)2 + (18)2 + (7)2 + (-22)2 + (5)2
= 1,444 + 2,025 + 169 + 64 + 576 + 289 + 576 + 121 + 324 + 49 + 484 + 25
= 6,146
So the Variance = 6,146 ÷ 12 = 512.166...
The Standard Deviation is just the square root of the Variance
= √(512.166...)
= 22.6 correct to 1 decimal place
Question 3
If each number is multiplied by 3, then the mean is also multiplied by 3.
The values of the differences, therefore, are also multiplied by 3
= The values of the squares of the differences are multiplied by 9 (32)
= The value of the variance is multiplied by 9
= The value of the standard deviation is multiplied by √9 = 3
The values of the differences, therefore, are also multiplied by 3
= The values of the squares of the differences are multiplied by 9 (32)
= The value of the variance is multiplied by 9
= The value of the standard deviation is multiplied by √9 = 3
Linear Equations Exercises
Question 1
First find the slope:
m = Rise/Run = 5/1 = 5
Next use the formula y - y1 = m(x - x1)
Substitute x1 = -1, y1 = -3 and m = 5
Therefore y - (-3) = 5(x - (-1))
Question 2
First find the slope:
m = Rise/Run = 5/4 = 1.25
Next use the formula y - y1 = m(x - x1)
Substitute x1 = 2, y1 = -2 and m = 1.25
= y - (-2) = 1.25(x - 2)
= y + 2 = 1.25x - 2.5
= y = 1.25x - 2.5 - 2
= y = 1.25x - 4.5
Question 3
First find the slope:
m = Rise/Run = -8/6 = -4/3
Next use the formula y - y1 = m(x - x1)
Substiute x1 = -4, y1 = 6 and m = -4/3
= y - 6 = -4/3(x - (-4))
= y - 6 = -4/3(x + 4)
= y - 6 = -4/3x -16/3
= y = -4/3x -16/3 + 6
= y = -4/3x - 16/3 + 18/3
= y = -4/3x + 2/3
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